8x+10=3x^2+45

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Solution for 8x+10=3x^2+45 equation: 



8x+10=3x^2+45

We move all terms to the left:

8x+10-(3x^2+45)=0

We get rid of parentheses

-3x^2+8x-45+10=0

We add all the numbers together, and all the variables

-3x^2+8x-35=0

a = -3; b = 8; c = -35;
Δ = b2-4ac
Δ = 82-4·(-3)·(-35)
Δ = -356
Delta is less than zero, so there is no solution for the equation

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